Pertanyaan
P kuadrat/q × (-p/q kuadrat)kuadrat × q kuadrat 4/p kuadrat 3
Ditanyakan oleh: USER1679
61 Dilihat
61 Jawaban
Jawaban (61)
p²/q × (-p/q²)² × q⁴/p³
= p²/q × p²/q⁴ × q⁴/p³
= p^(2+2-3) × q^(4-4-1)
= p¹ × q-¹
= p/q
tanda ^ pangkat yah
= p²/q × p²/q⁴ × q⁴/p³
= p^(2+2-3) × q^(4-4-1)
= p¹ × q-¹
= p/q
tanda ^ pangkat yah
p²/q x (-p/q²)² x q⁴/p³
= p²/q x p²/q⁴ x q⁴/p³
= (p² x p² x q⁴)/(q x q⁴ x p³)
= (p²⁺² x q⁴)/(q¹⁺⁴ x p³)
= (p⁴ x q⁴)/(q⁵ x p³)
= (p⁴ x q⁴)/(p³ x q⁵)
= p⁴⁻³ x q⁴⁻⁵
= p¹ x q⁻¹
= p x 1/q
= p/q
= p²/q x p²/q⁴ x q⁴/p³
= (p² x p² x q⁴)/(q x q⁴ x p³)
= (p²⁺² x q⁴)/(q¹⁺⁴ x p³)
= (p⁴ x q⁴)/(q⁵ x p³)
= (p⁴ x q⁴)/(p³ x q⁵)
= p⁴⁻³ x q⁴⁻⁵
= p¹ x q⁻¹
= p x 1/q
= p/q