Question
exercice 2: Factoriser les expressions suivantes :
A(x)=(x-3) (x+7)-(2x+1) (x+7)
B(x)=(2x-3)² - (2x-3) (x+1)
C(x)=25x²-49
D(x)=(x-1)² -(x+1)²
A(x)=(x-3) (x+7)-(2x+1) (x+7)
B(x)=(2x-3)² - (2x-3) (x+1)
C(x)=25x²-49
D(x)=(x-1)² -(x+1)²
Asked by: USER3891
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173 Answers
Answer (173)
A(x)=(x-3) (x+7)-(2x+1) (x+7)
a = (x+7)(x-3-2x-1)
a = (x+7)(-x-4)
B(x)=(2x-3)² - (2x-3) (x+1)
b = (2x-3)(2x-3-x-1)
b =(2x-3)(x-4)
C(x)=25x²-49
c = (5x-7)(5x+7)
D(x)=(x-1)² -(x+1)² = 0 ou si tu preferes
d = (x-1-x-1)(x-1+x+1)
d = 0 (2x)
d =0
a = (x+7)(x-3-2x-1)
a = (x+7)(-x-4)
B(x)=(2x-3)² - (2x-3) (x+1)
b = (2x-3)(2x-3-x-1)
b =(2x-3)(x-4)
C(x)=25x²-49
c = (5x-7)(5x+7)
D(x)=(x-1)² -(x+1)² = 0 ou si tu preferes
d = (x-1-x-1)(x-1+x+1)
d = 0 (2x)
d =0