bonjour A=(4x+3)au carre a développer
[tex]a = (4 \\ }^{?} }^{2} [/tex]
​

By: USER1631
27 Agustus 2025 mathematiques 5 minutes
4.5
83 views 83 comments 13 shares

Question

Grade: Education Subject: mathematiques
bonjour A=(4x+3)au carre a développer
[tex]a = (4 \\ }^{?} }^{2} [/tex]
​
Asked by:
83 Viewed 83 Answers

Answer (83)

Best Answer
(68)
(4x+3)^2 =
(4x) ^2 + 2 x 4x x 3 + 3^2 =
16x^2 + 24x + 9
Answered on 27 Agustus 2025
(324)

Réponse :

Salut ,

a[tex](4X+3)²[/tex]=

(4X+3)²

(4X)²+2*4X*3+3²

16X²+24X+9

Courage !

Explications étape par étape :

Answered on 27 Agustus 2025

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2) On multiplie ce nombre par 4
3) On ajoute 7 au résultat
4) Fin 

Question: 
- Laurent a trouvé 34 comme résultat quel nombre avait choisit au départ ?

+ Trouvé le

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