Question
A coffee pot in the form of a circular cylinder of radius 3 in. is being filled with water flowing at a constant rate. if the water level is rising at the rate of 0.4 in./sec, what is the rate at which water is flowing into the coffee pot? (round your answer to two decimal places.)
Asked by: USER4228
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282 Answers
Answer (282)
This is a question volumetric flow rate.
In 1 second, water rises with 0.4 in.
Additionally,
Volume filled in 1 second = A*0.4, A = surface area of the circular cylinder.
Where,
A = πR^2 = π*3^2 = 9π in^2
Therefore,
Volumetric flow rate = 9π*0.4 = 11.31 in^3/s
In terms of liters/s,
1 in^3 = 0.0163871 litres
Then,
11.31 in^3/s = 11.31*0.0163871 ≈ 0.19 l/s
In 1 second, water rises with 0.4 in.
Additionally,
Volume filled in 1 second = A*0.4, A = surface area of the circular cylinder.
Where,
A = πR^2 = π*3^2 = 9π in^2
Therefore,
Volumetric flow rate = 9π*0.4 = 11.31 in^3/s
In terms of liters/s,
1 in^3 = 0.0163871 litres
Then,
11.31 in^3/s = 11.31*0.0163871 ≈ 0.19 l/s