$6.95 with a markup of 33%

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Grade: Education Subject: mathematics
$6.95 with a markup of 33%
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[tex] p\%=\dfrac{p}{100}\\\\33\%=\dfrac{33}{100}=0.33\\\\33\%\ of\ \$6.95\ is\ equal\ 0.33\cdot\$6.95=\$2.2935\approx\$2.29\\\\Answer:\ \$6.95+\$2.29=\$9.24 [/tex]